- #1

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Example :

Values in time = 2s Error in time = +-0.05

Percentage Error = (0.05/2)*100

**+-2.5%?**

Should i be using relative errors?

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- Thread starter Firepanda
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- #1

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Example :

Values in time = 2s Error in time = +-0.05

Percentage Error = (0.05/2)*100

Should i be using relative errors?

- #2

berkeman

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Your answer looks correct to me. +-0.025/1 is +- 2.5%.

- #3

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so the method is correct? :)

and i shouldnt be using relative errors?

and i shouldnt be using relative errors?

- #4

berkeman

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- #5

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dont worry :P the example i used is what i originally thought was correct, just wanted confirmation :)

edit*

one quick question though, if i am using the equation s = ut + 0.5at^2

and the % error in ut is 1% and the % error in 0.5at^2 is 3% then what would the overall error in s be?

edit*

one quick question though, if i am using the equation s = ut + 0.5at^2

and the % error in ut is 1% and the % error in 0.5at^2 is 3% then what would the overall error in s be?

Last edited:

- #6

berkeman

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one quick question though, if i am using the equation s = ut + 0.5at^2

and the % error in ut is 1% and the % error in 0.5at^2 is 3% then what would the overall error in s be?

It's usually safest to compute what the answer is without error, and then what it is with all the errors added in, and then take the ratio to see what your final errors are.

So what is the nominal anwswer in your equation with no error?

And what is the largest you can make the answer with errors included?

And what is the smallest you can make the answer with errors included?

Then your +- errors would be

(1 - biggest/nominal) * 100%

(1 - smallest/nominal) * 100%

So in your question above, you need real numbers to figure out what the % errors are. You can't just add the percentages, because they can act on very different size numbers. Does that make sense?

- #7

berkeman

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Quiz Question -- Why is it different when you are multiplying terms? What is the total error for this:

A = B * C

when the error in B is +-2% and the error in C is +-3% ?

- #8

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if im correct when u multiply approximations you add the % errors

also from what u said before i assume my final error will lie in a range of the answer , s

such as if s=30 then x<30<y

- #9

berkeman

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i think its +-5% from what ive done before

if im correct when u multiply approximations you add the % errors

1 - (1.02) * (1.03) = ?

1 - (0.98) * (0.97) = ?

So it's close to adding, but not exact.

also from what u said before i assume my final error will lie in a range of the answer , s

such as if s=30 then x<30<y

Sorry, I'm not tracking what you are saying.

- #10

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1 - (1.02) * (1.03) = ?

1 - (0.98) * (0.97) = ?

So it's close to adding, but not exact.

so i can say that adding the % errors when multiply approximations is ok for small % errors?

forget what i was saying before, was babbling on a bit :)

- #11

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*edit soz was being stupid

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